b^2-26b+48=0

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Solution for b^2-26b+48=0 equation:


Simplifying
b2 + -26b + 48 = 0

Reorder the terms:
48 + -26b + b2 = 0

Solving
48 + -26b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b)(24 + -1b) = 0

Subproblem 1

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Subproblem 2

Set the factor '(24 + -1b)' equal to zero and attempt to solve: Simplifying 24 + -1b = 0 Solving 24 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-24' to each side of the equation. 24 + -24 + -1b = 0 + -24 Combine like terms: 24 + -24 = 0 0 + -1b = 0 + -24 -1b = 0 + -24 Combine like terms: 0 + -24 = -24 -1b = -24 Divide each side by '-1'. b = 24 Simplifying b = 24

Solution

b = {2, 24}

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